Physics, asked by nichi, 1 year ago

What is the value of current that will flow through a resistor of 5 when a potential difference of 3v is applied across it's end

Answers

Answered by P1234
0
Consider a task of moving a charge from A to B in a uniform electric field. Let this movement be against to the electric field. Some work will be done by an external force on this charge and this work will change the potential energy to a higher value. The amount of work done is equal to the change in potential energy. This change in potential energy will result in a difference in potential between the two points A and B. This difference in potential is called Potential Difference and it is measured in Volts (V).
Potential Difference is denoted by ∆V and is defined as the difference in potential or voltage between two points.
If VA is the potential at A and VB is the potential at B, then from the definition of potential difference,
∆VBA = VB – VA
For example, consider the following resistor R1.
The potential applied at one end of the resistor (Point A) is 8 V and the potential at other end of the resistor (Point B) is 5 V.
The potential difference between the two points A and B is
VAB = 8 – 5 = 3 V.
This is also called as the Potential across the resistor.
Current flows in an electrical circuit in the form of charge whereas potential doesn’t flow or move. Potential difference is applied between two points.
The unit of potential difference between two points is Volt. Volt is defined as the potential drop across a 1 Ohm (Ω) resistor with 1 Ampere of current flowing through it.
Hence
1 Volt = 1 Ampere×1 Ohm
V = I × R
According to Ohm’s law, the current flowing in a linear circuit is directly proportional to the potential difference across the circuit. Hence if the potential difference applied across the circuit is greater, then the current flowing in the circuit is larger.
For example if one side of a 1 Ω resistor is at a potential of 8 V and the other side is at 2 V, then the potential difference across the resistor is 5 V. The current flowing in the resistor is
I = V/R= 5V/1 Ω = 5 Amps.
Now for the same 1 Ω resistor, if the potential applied at one end is raised from 8 V to 12 V and at the other end it is raised from 2 V to 4 V. Then the potential difference across the resistor is now at 8 V. The current flowing in the resistor in this situation is 8 Amps.
I = V/R= 8V/1 Ω = 8 Amps.
Generally in electrical circuits the lower potential is earth or ground. This value is usually considered 0 V. Hence the potential difference is equal to the applied voltage. Earth is considered as the common point in a circuit. This reference of earth or ground as common point in electrical circuits is useful in easy understanding of the circuit. Potential difference is also called voltage.
Voltages connected in series are added to give total voltage in a circuit. This can be observed in resistors in series connection. If V1, V2 and V3 are connected in series then total voltage VT is given by
V = V1 + V2 +V3.
In case of elements connected in parallel, the voltage across them is equal. This can be observed in resistors in parallel tutorial.
V = V1 = V2 = V3.
Answered by lindawoodlock
0
I think that the answer is 0.6A
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