what is the value of d/dx*sin^2x+cos^2x
Answers
Answered by
1
Step-by-step explanation:
From the given
y
=
sin
2
x
+
cos
2
x
The right side of the equation is
=
1
y
=
1
d
y
d
x
=
d
d
x
(
1
)
=
0
or we can do it this way.
y
=
sin
2
x
+
cos
2
x
d
y
d
x
=
2
⋅
(
sin
x
)
2
−
1
⋅
d
d
x
(
sin
x
)
+
2
(
cos
x
)
2
−
1
d
d
x
(
cos
x
)
d
y
d
x
=
2
⋅
sin
x
⋅
cos
x
+
2
⋅
cos
x
⋅
(
−
sin
x
)
d
y
d
x
=
2
⋅
sin
x
⋅
cos
x
−
2
⋅
sin
x
⋅
cos
x
d
y
d
x
=
0
God bless....I hope the explanation is useful.
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Answered by
0
Step-by-step explanation:
2 sin x cos x - 2 cos x sin x
= 0
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