What is the value of D if the equation 2x + y = 3 and 3x – 2y = 4 are solved by cramer’s method.
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comparing 2x + y=3 with a1x1 + b1y1 = c1 and 3x-2y =4 with a2x2 - b2y2 = c2
then a1= 2 , b1 = 1 , c1= 3
a2 = 3 , b2= -2 , c2=4
by determinants method
D = |a1 b1 |
|a2 b2 |
= 2. 3
1. -2
= 2 × (-2) - 3 × 1
= -4 - 3
= -7
.: D = -7
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