Math, asked by ISHUKAKU78951, 7 months ago

What is the value of discriminant for a quadratic equation 2x²-3x-4=0

Answers

Answered by varnitkalraalt

0

Answer:

D = 41.

Step-by-step explanation:

p(x)=2x^2-3x-4=0

a = 2 ; b = -3 ; c = -4

Discriminant(D) = b^2 - 4(a.c)

= (-3)^2 - 4(2)(-4)

= 9 - 4(-8)

= 9 - (-32)

= 9 + 32

=> 41 ans

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