Question

what is the value of electric potential on equatorial line of an electric dipole

Answer 1

it is Zero...

we know that Electric potetial due to a point charge at any location r is V = kq / r
where
k = coulomb's constant
q = charge particle which is resposibld for creating potentials at location r
r = distance from the charge q

Note that : Negative charge create negative potential and positive charge create positive potential..

So ,
Potential due to +q at location r is V = kq /r and
Potentisl due to -q at location r is V = - kq / r

Potantial is a scalar quantity...So it can be added or subtracted by simple rule of algebra..

See snap

Answer 2

             hey ..let me help u

According to the diagram ,

we need to find the electric potential of point p

and we know that

V = $Kq/r$

since V is a scalar quatity . we can add as well as subtract them .

$V_{-q}$ = $-Kq/ \sqrt{r^{2}+l^{2} }$

$V_{q}$  = $Kq/ \sqrt{r^{2}+l^{2} }$

adding

V =  $V_{-q}$ + $V_{q}$

V = $-Kq/ \sqrt{r^{2}+l^{2} }$ +  $Kq/ \sqrt{r^{2}+l^{2} }$

V = 0