What is the value of equation
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hey
here is ur answer
LET 2^x=3^y=(1/6)^z=k
Therefore,
K^(1/x)=2
K^(1/y)=3
K^(1/z)=(1/6)
Multiply these 3 equations to get:
K^[(1/x)+(1/y)+(1/z)]=1
Hence we can conclude that either k=1 ( which is totally false) or power is equal to “0”.
The correct answer is : [(1/x)+(1/y)+(1/z)]=0
I hope this will help✌
#Prem✌
here is ur answer
LET 2^x=3^y=(1/6)^z=k
Therefore,
K^(1/x)=2
K^(1/y)=3
K^(1/z)=(1/6)
Multiply these 3 equations to get:
K^[(1/x)+(1/y)+(1/z)]=1
Hence we can conclude that either k=1 ( which is totally false) or power is equal to “0”.
The correct answer is : [(1/x)+(1/y)+(1/z)]=0
I hope this will help✌
#Prem✌
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