what is the value of f(16)-f(0) when f(x)=4x-8
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Answered by
3
Answer:
First find value of f(16)= 4(16)-8=64-8=56
Similarly, we shall find f(0)=4(0)-8=0-8= -8
substitute the values in given equation
thus,
f(16)-f(0)= 56-(-8)=56+8=64
Answered by
4
Given,
f(x)=4x-8
To find,
The value of f (16) - f (0)
Solution,
⇒ f(x) = 4x - 8.
To find f (16) we can simply substitute x as 16 in the given function.
Therefore,
⇒ f ( 16 ) = 4(16) - 8
⇒ f ( 16 ) = 64 - 8 .
⇒ f ( 16 ) = 56.
Similarly we can find f ( 0 ) by substituting x as 0 in the function f ( x ).
⇒ f ( 0 ) = 4(0) - 8
⇒ f ( 0 ) = 0 - 8
⇒ f ( 0 ) = -8.
Now, f (16) - f (0) = 56 - (-8)
⇒ 56 + 8
⇒ 64.
Hence, The value of f (16) - f (0) = 64.
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