Question

What is the value of f(4000) for the function below?
def f(x):
d=0
while x >= 1:
(x,d) = (x/5,d+1)
return(d)

Answer 1

Answ

Step-by-step explanation:

Answer 2

The value of f(4000) for the given function is 6.

The breakdown analysis of each line of the code is given below.

1. def f(x): -f(x) is being defined in this line.

2. d=0 -d is assigned the value 0.

3. while x >= 1: -'while' loop starts and continues until the condition x>=1 is not satisfied

4. (x,d) = (x/5,d+1) -for the existing values of x and d x becomes a fifth of its prevailing value and d increases by 1.

5. return(d) -the final valueiof d is displayed to the user.

In the code above the while loop is executed 6 times until the remainder attains a value less than 1 when divided by 5.