Question

what is the value of g on earth.
for class 9th physics chapter on the lesson Gravitational force....
plz give me answer in positive way..
And dont spam plzzz..

Who will answer first with the correct answer I will mark them as Brainliest and I will thank there answers..​

Answer 1

Explanation:

g=GMe/R²e

calculation of value of 'g'

we are given,

Me=6×10^24kg,Re=6.4×10^6

G=6.67×10^-11 Nm²/kg²

therefore, g=6.67×10^-11×6×10^24/(6.4×10^6)²

=9.8 m/s²

therefore, g=9.8 m/s².

hope it will help you.

Answer 2

AnSwEr :

Value of g on surface of Earth is 9.8 m/s².

________________

Derivation of Newton's Law of Gravitation :

It states that, acceleration due to gravity is directly proportional to the Product of masses of objects, and inversely proportional to the square of distance between objects. It is also called as Inverse Square Law.

Mathematically,

$\implies \sf{g\ \propto\ m_1 m_2} \\ \\ \\ \\ \implies \sf{g\ \propto\ \dfrac{1}{r^2}} \\ \\ \\ \\ \implies \sf{g\ \propto\ \dfrac{m_1 m_2}{r^2}} \\ \\ \\ \\ \implies \sf{g\ =\ G \dfrac{m_1 m_2}{r^2}} \\ \\ \\ \\ \sf{Where} \small \begin{cases} \sf{m_1\ and\ m_2\ are\ masses\ of\ two\ objects} \\ \\ \sf{r^2\ is\ square\ in\ distance\ between\ objects} \\ \\ \sf{G\ is\ Gravitational\ constant} \end{cases}$