Question

What is the value of 'g' on moon?

Given:

M=7.4*10^22 kg

G= 6.67*10^-11 Nm^2/ kg^2

r= 1.74*10^6 m

Dont use google or i will report you

Answer 1

Answer :-

1.6m/s^2

Explanation :-

Given :

The mass of the moon is 7.35 × 10^22Kg.

The radius of the moon is 1.74 × 10^6 m

Universal gravitational force = 6.67 × 10^-11 Nm^2/ kg^2

To Find :

Gravitational acceleration on moon = ?

Solution :

We know,

$\boxed{\sf{}g= G\dfrac{M}{r^2}}$

where,

g is the gravitational acceleration,

G is the universal gravitational force,

M is the mass of the moon and,

r is the radius of the moon.

Put their values and solve it,

$\sf{}\implies g=\dfrac{6.67 \times 10^{-11}\times 7.35 \times 10^{22}}{(1.74\times 10^6)}$

$\sf{}\implies g=\dfrac{6.67 \times 10^{-11}\times 7.35 \times 10^{22}}{1.74\times 10^6\times 1.74\times 10^6}$

$\sf{}\implies g=\dfrac{6.67 \times 10^{-11}\times 7.35 × 10^{22}}{1.74\times 10^6\times 1.74\times 10^6}$

$\sf{}\implies g=\dfrac{49.02 \times 10^{-11+22}}{3.02\times 10^{6+6}}$

$\sf{}\implies g=\dfrac{49.02 \times 10^{11}}{3.02\times 10^{12}}$

$\sf{}\implies g=16.23 \times 10^{11-12}$

$\sf{}\implies g=16.23 \times 10^{-1}$

$\sf{}\implies g=16.23 \times \dfrac{1}{10^1}$

$\sf{}\implies g=\dfrac{16.23}{10}$

$\sf{}\therefore g=1.6m/s^2$

Therefore,value of g on the moon is equal to 1.6m/s^2

Answer 2

Given:

• Mass = M= $7.4 \times {10}^{22} kg$
• G = $6.67 \times {10}^{ - 11} \: n {m}^{2} {kg}^{2}$
• r = $1.74 \times {10}^{6} m$

━━━━━━━━━━━━━━━

Need to find:

• Value of g=?

━━━━━━━━━━━━━━━

Solution:

We know,

$\purple{\boxed{\bold{g= \dfrac{G \: M \: }{ {r}^{2} }}}}$

$\implies \: g \: = \dfrac{6.67 \times {10}^{ - 11} \times 7.4 \times {10}^{22}}{1.74 \times {10}^{6} \times 1.74 \times {10}^{6} }$

$\implies \: g = \dfrac{6.67 \times 7.4}{1.74 \times 1.74} \times \dfrac{ {10}^{ - 11} \times {10}^{22} }{ {10}^{6} \times {10}^{6} }$

$\implies \: g \: = \dfrac{49.358}{3.0276} \times {10}^{22 - 11 - 6 - 6}$

$\implies \: g = 15.41 \times {10}^{ - 1}$

$\red{\large{\bold{\boxed{ \implies \: g = 1.54 m/{s}^{2}}}}}$