Question

What is the value of i^1+3+5+....+(2n+1)
CHAPTER COMPLEX NUMBERS​

Answer 1

Step-by-step explanation:

I1+3+5+...(2n+1)

=I(n+1)2

=In2+2n+1           

Let n=2k 

I4k2+4k+1

I4(k2+k)+1

=I4(k2+k)×I

=1×I

=I

If n is odd, n+1 will be even 

Let n+1=2m 

∴I(n+1)2=I(2m)2=I4m2

 =1