what is the value of √i +√-i
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Answer:
(1+i)
5
+(1−i)
5
i=
−1
(1+i)
5
=
5
C
∘
i
∘
+
5
C
1
i
1
+
5
C
2
i
2
+
5
C
3
i
3
+
5
C
4
i
4
+
5
C
5
i
5
(1−i)
5
=
5
C
∘
i
∘
−
5
C
1
i
1
+
5
C
2
i
2
−
5
C
3
i
3
+
5
C
4
i
4
−
5
C
5
i
5
(1+i)
5
+(1−i)
5
=2(
5
C
0
+
5
C
2
(−1)+
5
C
4
(1))
=2(1+
2×1
2×4
+5)=−8
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