Question

what is the value of inductance
for which the current is maximum in a series LCR circuit with c 10 μF and ω =1000 S^-1 ?​

Answer 1

Answer:

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Explanation:

In physics, a force is any influence that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity, i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity

Answer 2

Solution : 100 mH

Explanation:

Current in LCR series circuit,

i = V / √ [R^2 + ( xL - xC ) ^2]

where, V is rms value of voltage R is Resistance, XL is inductive resistance and XC is capacitive resistance.

For current to be maximum denominator should be minimum which can be done, that is during the resonance of series LCR circuit

XL = XC ie ωL = 1/ωC

or L = 1 /ω^2 C _[i]

Given, ω = 1000 s^-1, C = 10μF = 10 × 10^-6 F

Hence,

L = 1 / ( 1000 )^2 × 10 × 10^-6

L = 0.1 H = 100mH

∴ The value of insurance is 100mH !