Question

What is the value of inductance L for which the current is maximum in a series LCR curcuit with C = 1010 μF and ω =1000 S^-1?​

Answer 1

Explanation:

The value of inductance L for which the current is maximum in series LCR circuit with C = 10 μF and ω = 1000 rad/s.

Answer 2

Explanation:

Current in LCR series circuit

i = V / √ [ R^2 + ( Xʟ - Xc )^2 ]

Where, V is rms value of voltage R us resiatance, Xʟ is inductive reactance and Xc us capacitive reactance

For current to be maximum denominator should be minimum which can be done, i.e during the resonance of series LCR circuit

=> Xʟ - Xc

=> ωL = 1 / ωC

=> L = 1 /ω^2C

Given:

ω = 1000 s^-1, C = 10 μF = 10 × 10^-6 F

Hence, L = 1 / [ ( 1000 )^2 × 10 × 10^-6]

L = 0.1 H = 100 mH

The value of inductance L is

100mH !

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