Math, asked by tanya031, 1 year ago

what is the value of iota^iota​


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Answers

Answered by QUEEN120806
0

Answer:

Step-by-step explanation:

e^ix =cos x +isin x;

if x=Ï€/2

e^iπ/2=cosπ/2+isinπ/2=i

i^i= (e^iπ/2)^i

i^i=e^-Ï€/2

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