Question

What is the value of iota's power
of iota

Answer 1

Answer:

i=

$i = \sqrt{ - 1}$

$i ^{2} { = - 1}$

$i {i}^{2} = - i$

$i { {}^{2} }^{2} = 1$

Answer 2

For

$i = \sqrt{ - 1}$

$\implies {i}^{i} = {e}^{ \frac{i \pi }{2} .i}$

$\implies {i}^{i} = {e}^{ - \frac{\pi}{2} }$

Which is a Pure Real Number However Irrational And Transcendental.

$\boxed{ \sqrt{ - 1} {}^{ \sqrt{ - 1} } = {e}^{ - \frac{\pi}{2} } ≈0.2078...} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$