what is the value of k, (-4) isba zero of the polynomial x2 - x - (2k-+2)
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Answered by
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Hey user here is your answer.......
----> To find- k
◆ Given equation- x^2-x-(2k+2)
◆(-4) is zeros so put x =-4
◆(-4)^2-(-4)-(2k+2)
◆16+8-2k-2
◆22-2k=0
◆-2k=-22
◆k=11
Hope it helps you☺️
#Rohan ( Maths aryabhatta)
----> To find- k
◆ Given equation- x^2-x-(2k+2)
◆(-4) is zeros so put x =-4
◆(-4)^2-(-4)-(2k+2)
◆16+8-2k-2
◆22-2k=0
◆-2k=-22
◆k=11
Hope it helps you☺️
#Rohan ( Maths aryabhatta)
Navdeep005:
thanks
welcome :)
no answer in will be 9 i think
Hey sis!! i think i dont have to Answer this question bcoz he used both sign +-
because sis is fool
Answered by
1
I make it on copy to understand you better.
Hope it helps.
Hope it helps.
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