Question

What is the value of k for which 2x2

-kx+k=0 has equal roots?​

Answer 1

Answer:

Hello Mate . Wassup

Step-by-step explanation:

The values of k = 4.

Given:

Quadratic equation 2x^{2}+Kx +2=02x

2

+Kx+2=0 has equal roots.

To find:

The values of k

Explanation:

General format of quadratic equation is ax^2+bx+c =0ax

2

+bx+c=0 .

If the roots of quadratic equation is equal then,

\sqrt{b^{2} \ -\ 4ac }=0

b

2

− 4ac

=0

Where,

a = coefficient of x²

b = coefficient of x

c = constant term.

\sqrt{b^{2} \ -\ 4ac }=0

b

2

− 4ac

=0

b² - 4ac =0

Comparing the quadratic equation

2x^{2}+Kx +2=02x

2

+Kx+2=0

b = k a=2 c=2

k² - 4×2×2 = 0

k² = 16

k = \sqrt{16}

16

k = 4

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