What is the value of k for which the quadratic equation 3x-kx+k=0 has equal roots?
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Answer:
k=12
Step-by-step explanation:
for equal roots D=0,than,
0=b^2-4ac
hence,
k^2-4×3×k=0
k^2-12k=0
k(k-12)=0
k-12=0
therefore,k=12
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