Question

:) What is the value of k for which the quadratis equation3x2-2y+11=0 and7x-4y=9​

Answer 1

Answer:

x=-1 and y=-4.

Step-by-step explanation:

We are given the equations,

3x+2y+11=03x+2y+11=0 , and, 7x-4y-9=07x−4y−9=0

Multiplying the first equation by 2, and adding,

\begin{gathered}6x+4y+22=0\\7x-4y-9=0\\--------\\13x+13=0\end{gathered}

6x+4y+22=0

7x−4y−9=0

−−−−−−−−

13x+13=0

Hence, 13x=-1313x=−13

and, x=-1x=−1

Putting the value of x in the first equation,

3(-1)+2y+11=03(−1)+2y+11=0

-3+11+2y=0−3+11+2y=0

2y+8=02y+8=0

And,

y=-4y=−4 .

Hence, x=-1x=−1 and y=-4y=−4 is the solution of this pair of equations.