Question

What is the value of k .For which the simultaneous equation 2x+3y=8 and 6x-ky=24 have infinitely many solutions? options are as follows

Answer 1

Step-by-step explanation:

$2x + 3y = 8 \\ x = \frac{8 - 3y}{2 } \\ applying \: the \: above \: value \: of \: x \: in \: equation \: 6x - ky = 24 \\ 6( \frac{8 - 3y}{2} ) - ky = 24 \\ 24 - 9y - ky = 24 \\ - 9y - ky = 0 \\ ky = - 9y \\ k = - 9$