What is the value of k for which the system of equations 3x² + 2y - 4 = 0 and 5x2 + ky + 8 = 0 has no
solution
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Answer:
For a system of equations a
1
x+b
1
y+c
1
=0;a
2
x+b
2
y+c
2
=0 to have no solution, the condition to be satisfied is
a
2
a
1
=
b
2
b
1
=
c
2
c
1
⇒
5
1
=
k
2
=
7
−3
∴ For k=10, the given system of equation has no solution.
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