Question

what is the value of k if 3x^2-kx+k=0​

Answer 1

Answer:

Therefore, the values of k for which the quadratic equation 3x2−2kx+12=0 will have equal roots are 6 and −6.

Answer 2

Step-by-step explanation:

I believe your Question was,

"What is the value of 'k', if 3x² - kx + k = 0 have equal roots."

3x² - kx + k = 0

ax² + bx + c = 0

where a = 3, b = (-k), c = k

Now,

If a Quadratic have equal roots then its Discriminant must be equal to 0

Discriminant = b² - 4ac

Here,

b² - 4ac = 0

Putting in the values,

(-k)² - 4(3)(k) = 0

k² - 12k = 0

k(k - 12) = 0

So,

k = 0 or (k - 12) = 0

k = 0 or k = 12

Hence,

When k = 0 or k = 12, 3x² - kx + k = 0 will have equal roots.

Hope it helped and believing you understood it........All the best