what is the value of ‘k’
if 4xcube minus 2 x square plus kx plus 5 leaves remainder minus10 when divided by 2x plus 1
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Answer:
k=2
Step-by-step explanation:
f(x)= 4x^3 - 2x^2 +kx+5
2x+1=0
therefore x= -1/2
f(-1/2)= -10
4(-1/2*-1/2*-1/2) - 2*(-1/2*-1/2) + k*(-1/2)+5= -10
-4/8 - 2/4 -k/2 = -15
-1/2-1/2-k/2 = -15
2+k = 30
therefore;
k=28
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