Math, asked by Rucsana, 10 months ago

What is the value of k if 7y*y-3y-k=35 when y =-2?​

Answers

Answered by Sunnyji123
2

Answer:k=-1

Step-by-step explanation:

7y2-3y-k = 35

WHEN y = -2

7(-2)2 - 3(-2)-k = 35

7(4) - (-6)-k = 35

28+6-k=35

34-k=35

-k=1

k=-1

Answered by davidorinate
0

Answer

k=13

Step-by-step explanation:

k is 13

because

7y*y-3y-k=35  and y= 2

therefore

7*2*2-3*2-k=35

14*2-6-k=35

22-k=35

make k subject of the formular

k=35-22

k=13

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