Math, asked by gabrieljohnas2007, 11 months ago

What is the value of $k$ if $-\frac23(k-6) = \frac32(k+6)$?



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Answers

Answered by Anonymous
3

Answer:

k = 110/3

Step-by-step explanation:

Equation is 23/(k - 6) = 32/(k + 6)

=> (k + 6) * 23 = 32 * (k - 6)

=> 23k + 138 = 32k - 192

=> 23k - 32k = -192 - 138

=> -9k = -330

=> k = 330/9

=> k = 110/3

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