Question

what is the value of k.If one root of the quadratic equation kx square root-7x+12=0 is 3

Answer 1

the value of K will be 1.... k is equal to 1.

Answer 2

$kx {}^{2} - 7x + 12 = 0 \\ x = 3 \\ k {3}^{2} - 7(3) + 12 = 0 \\ 9k - 21 + 12 = 0 \\ 9k - 9 = 0 \\ 9k = 9 \\ k = 1$
value of k is 1