Question

what is the value of k if one root of the quadratic equation kx²-7x+12=0 is 3

Answer 1

Answer:

$k = 1$

Step-by-step explanation:

$kx {}^{2} - 7x + 12 = 0$

$3 \: is \: the \: root$

$substitute \: x = 3$

$(3) {}^{2} k - 7(3) + 12 = 0$

$9k = 9$

$k = 1$

hope it will help u