Question

what is the value of k if the equation x squares -8X + K =0 have real and equal roots

Answer 1

here a=1 , b = -8k and c = k
Discriminant = 0
b² - 4ac = 0
(-8k)² - 4 × 1 × k = 0
64k² - 4k = 0
4k ( 16k - 1 ) = 0
4k = 0 or. 16k - 1 = 0
k = 0. 16k = 1
k = 1/16

Answer 2

A= 1 , B =-8 ,C= k

Now using the formula,
b square-4ac
For equal zeros the condition is. b square -4ac= 0

Now putting the values,
(-8)square-4(1)*(k)=0
64-4K= 0
-4K=-64
K=-64/-4 = 16
K = 16