Math, asked by samrina, 1 year ago

what is the value of "k" if the line 4x-ky-12=0 is perpendicular to the line with equation 6x-3y=0

Answers

Answered by sunnyboy96

0

Step-by-step explanation:

4x-ky=12 y= 6x/3

y= 2x

ky=4x-12

k=4x-12/y

k= 4x-12/2x

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