Question

what is the value of k, if the root of kx^2+24x+16=0 are real and equal​

Answer 1

Answer:

k=24

Step-by-step explanation:

kx^2+24x+16=0

since roots are equal and real,

$b^{2}$-4ac=0

a=k , b=24 , c=16

$24^{2}$-4(k)(16)=0

576-64k=0

64k=576

k=576/24

k=24