Question

What is the value of k, if the roots of 2y²-6y+k=0 are real and equal​

Answer 1

Answer:

comparing given equation with ax²+bx+c=0

a = 2 ,b = -6 , c = k

b²-4ac

= (-6)²-4×2×k

= 36 -8k

but roots are real and equal

b²-4ac =0

36-8k=0

-8k = 0-36

-8k=-36

-k = -36/8

-k = - 9/2

k = 9/2

Answer 2

Answer:

Answer:

comparing given equation with ax²+bx+c=0

a = 2 ,b = -6 , c = k

b²-4ac

= (-6)²-4×2×k

= 36 -8k

but roots are real and equal

b²-4ac =0

36-8k=0

-8k = 0-36

-8k=-36

-k = -36/8

-k = - 9/2

k = 9/2

Step-by-step explanation:

Hope this answer will help you.