What is the value of k, if the roots of 2y²-6y+k=0 are real and equal
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Answered by
0
Answer:
comparing given equation with ax²+bx+c=0
a = 2 ,b = -6 , c = k
b²-4ac
= (-6)²-4×2×k
= 36 -8k
but roots are real and equal
b²-4ac =0
36-8k=0
-8k = 0-36
-8k=-36
-k = -36/8
-k = - 9/2
k = 9/2
Answered by
2
Answer:
Answer:
comparing given equation with ax²+bx+c=0
a = 2 ,b = -6 , c = k
b²-4ac
= (-6)²-4×2×k
= 36 -8k
but roots are real and equal
b²-4ac =0
36-8k=0
-8k = 0-36
-8k=-36
-k = -36/8
-k = - 9/2
k = 9/2
Step-by-step explanation:
Hope this answer will help you.
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