Math, asked by vivekgaikwad2005, 3 months ago

What is the value of k, if the roots of kx^2 +24x + 16 = 0 are real and equal?
(A) 9
(B) -9
(C) 25
(D) – 25​

Answers

Answered by patsun27
0

Answer:

a.) 9

Step-by-step explanation:

a= k

b=24

c=16

b^2-4ac=0

(24)^2-4(k)(16)=0

576-64k=0

576=64k

k=576/64

k=9

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