What is the value of k, if the roots of kx^2 +24x + 16 = 0 are real and equal?
(A) 9
(B) -9
(C) 25
(D) – 25
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Answer:
a.) 9
Step-by-step explanation:
a= k
b=24
c=16
b^2-4ac=0
(24)^2-4(k)(16)=0
576-64k=0
576=64k
k=576/64
k=9
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