what is the value of k if the value of Dy for the equation 3x + y =1 and 2x - ky = 3 is 7
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Answer:
3x+ y=1
3x=y- 1
x= y-1 / 3
2(y-1/3) - ky=3
2y-2- ky =3×3
2y-ky =9+2
y(2-k) =11
2-k= 11/y
-k=11×2/y
-k=22/y
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