Question

What is the value of k, if the value of Dy for the equation 3x+y=1 and 2x-ky=3 is 7?​

Answer 1

Answer:

Correct option is

B

+2

3x+y=1

(2k−1)x+(k−1)y=(2k+1)

For no solution

a

2

a

1

=

b

2

b

1



=

c

2

c

1

Then

2k−1

3

=

k−1

1



=

2k+1

1

⇒3k−3=2k−1⇒k=2