what is the value of k if value of Dy for the equation 3x+y=1 and 2x - ky =3 is 7?
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Step-by-step explanation:
solve\:for\:x,\:3x+y=1\quad :\quad x=\frac{1-y}{3}solveforx,3x+y=1:x=
3
1−y
Step-by-step explanation:
\mathrm{Subtract\:}y\mathrm{\:from\:both\:sides}Subtractyfrombothsides
3x+y-y=1-y3x+y−y=1−y
3x=1-y3x=1−y
\mathrm{Divide\:both\:sides\:by\:}3Dividebothsidesby3
\frac{3x}{3}=\frac{1}{3}-\frac{y}{3}
3
3x
=
3
1
−
3
y
x=\frac{1-y}{3}x=
3
1−y
____________________________________
since,x=2
y=-3
2×2-k(-3)=3
4+k=3
k=-1
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