What is the value of k if (x – 1) is a factor of ka² -√2x+1?
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Answer:
√2 - 1
Step-by-step explanation:
x - 1 is factor of kx² - √2x + 1.
So, let x - 1 = 0.
∴ x = 1
Putting x = 1 in kx² - √2x + 1,
k(1)² - √2(1) + 1 = 0
k - √2 + 1 = 0
∴ k = 0 - (-√2 + 1) => √2 - 1 (Minus and minus combine to become plus.)
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