Math, asked by londhesmita78, 11 months ago

what is the value of k in kx(x-2)+6=0 ​

Answers

Answered by sireesharani64
1

Answer:

Step-by-step explanation:

kx(x-2)+6=0

kx^2-2kx+6=0

Here b^2-4ac<0

So it will not have any root or solution.

Hence,it will have imaginary roots.

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