Question

What is the value of k in kx²-3x-10=0 if its discriminant is 89?

Answer 1

D = b^2 - 4ac

89 = (-3)^2-4 k(-10)

89= 9 +40k

89-9 = 40 k

k = 80÷40

k=2

Answer 2

Given:

kx²-3x-10=0

discriminant = 89

A discriminant is a value calculated from a quadratic equation.

Quadratic equation ax2 + bx + c

The discriminant, D = b² - 4ac

Here a=k, b=-3, c=-10

D=(-3)² - 4(k)(-10)

89=9 + 40k

89-9=40k

40k=80

k=80/40

k=2

Hence the value of k is 2