What is the value of k in the expression, sec? 0 (1 + sin e) (1 - sin 6) = K?
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Answer:
sec
2
θ(1+sinθ)(1−sinθ)=k
sec
2
θ(1−sin
2
θ)=k
sec
2
θcos
2
θ=k
sec
2
θ⋅
sec
2
θ
1
=k
1=k
∴k=1.
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