what is the value of k ??? please give me the answer with reason
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equation to be solved: 5m^2+2m+k=0 , and the root of this equation is -7/5(given)
therefore, putting the value of m=-7/5 in the equation:
=5m^2 + 2m + k=0
=5(-7/5)^2 +2(-7/5) + k=0
=5(49/25)+2(-7/5) +k =0
= 49/5+2(-7/5) + k=0
=(49-16)/5 + k=0
=33/5 + k=0
=hence, k=33/5
NPharshini2003:
bro what is the value of - 7X 2
and u have done two mistakes
u had solved wrong
Answered by
1
Think that alpha is - 7/5
Alpha +beta= - 2/5
Beta+(-7/5)=-2/5
beta = - 2/5 + 7/5
beta = 1
Alpha X beta = k
-7/5 X 1 =k/5
-7/5 = k/5
K= - 7
Alpha +beta= - 2/5
Beta+(-7/5)=-2/5
beta = - 2/5 + 7/5
beta = 1
Alpha X beta = k
-7/5 X 1 =k/5
-7/5 = k/5
K= - 7
u can also solve by this method
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