Question

what is the value of k so that the pair of linear equation kx-y=2 and 6x-2y=3 have unique solution

Answer 1

Step-by-step explanation:

a1/a2 not= b1/b2

k/6=1/-2

-2k=6

k=6/-2

k= -3

Answer 2

Answer:

answer change accordingly as the value of k

Step-by-step explanation:

multiply 1st eqn by 2

2kx-2y = 4

6x-2y = 3

2kx-6x =1

when k not equal to zero k =1

-4x =1

x= -1/4 y = -3/7