Question

what is the value of k when 2x-6x​

Answer 1

Answer:

complex roots always occur in conjugate pair

2x

2

−6x+k=0

sum=3

product =

2

k

one root is

2

α+5i

other root is

2

α−5i

sum=

2

α+5i

+

2

α−5i

=3

α=3

product = k = (

2

3+5i

)(

2

3−5i

)

=

4

9−25i

2

=

4

9+25

=

2

17

Answer 2

Answer:

The value of k when 4x-12x