Question

What is the value of k4fecn6 in van't hoff factor?

Answer 1

Answer:

Vant's hoff factor = Totalnumberofmolesafterdissociationtotalnumberofinitialmoles

K4[Fe(CN)6]=4K++[Fe(CN)6]4−

∴ vant's hoff factor = 5

Because total number of ions after dissociation is 5

Answer 2

Answer:

Answer:

Vant's hoff factor = Totalnumberofmolesafterdissociationtotalnumberofinitialmoles

K4[Fe(CN)6]=4K++[Fe(CN)6]4−

∴ vant's hoff factor = 5

Because total number of ions after dissociation is 5

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Explanation: