Question

What is the value of Kc for the reaction 2A(g) + 3B(g) mc014-1.jpg 2C(g) + D(g) if at equilibrium [A] = 0.60 M, [B] = 0.30 M, [C] = 0.10 M and [D] = 0.50 M?

Answer 1

Explanation:

A+3B⇋2C+D

Initial concentration a a/2 0 0

At equilibrium (a-x) (a/2-3x) 2x x

We have been given that at equilibrium moles of B is half of mole of C

i.e.

2

a

−3x=

2

1

(2x)

x=

8

a

Therefore, the maount of B reacted =3x=

8

3a

Initial amount of B =

2

a

So, % of B reacted =

Initial amount of B

Amount of B reacted

×100

% of B reacted =

2

a

8

3a

×100=75%