Question

What is the value of \large \left(5r+\frac{1}{5}\right)^2 when r = 0?

Answer 1

17/5 = 3.4 is your answer

Answer 2

Given :    $\large \left(5r+\dfrac{1}{5}\right)^2$

To Find :  Value if r   = 0

Solution:

$\large \left(5r+\dfrac{1}{5}\right)^2$

r = 0

Substitute value of r is expression

$=\large \left(5\times0+\dfrac{1}{5}\right)^2$

Any number multiplied by zero is Zero

$=\large \left(0+\dfrac{1}{5}\right)^2$

Adding 0 to any number does not change value

$= \large \left( \dfrac{1}{5}\right)^2$

 $=\dfrac{1^2}{5^2}$

= 1/25

Value of  $\large \left(5r+\dfrac{1}{5}\right)^2$ is  1/25  when r = 0

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