Question

what is the value of latent heat of fusion of fusion of 2gm ice​

Answer 1

Answer:

80cal/g

Explanation:

it is constant value . the heat required to convert this 2g ice at 0 degrees to 2g water at 0degrees is 80×2=160cal.

but the latent heat of vaporisation of water is constant

Answer 2

Explanation:

Latent heat of ice is 80 calories per gram or 336j per gram

So for 2 g it is = 160cal or 672joules

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