Question

What is the value of latent heat of vapourisation of boiling water of 2 grams ?​

Answer 1

When a material in liquid state is given energy, it changes its phase from liquid to vapor; the energy absorbed in this process is called heat of vaporization. The heat of vaporization of water is about 2,260 kJ/kg, which is equal to 40.8 kJ/mol

Answer 2

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Thus the latent heat of vaporization for 2 grams is 1130 x 10^4 KJ / g. Explanation: The amount of heat energy that is absorbed or released by a substance during the change in its physical state is called the latent heat of vaporization. Water absorbs 2260 KJ/kg of heat energy to vaporize.