Math, asked by scarlet333, 8 months ago

what is the value of limit x tends to 0, (sin nx-nsinx)/x(cos nx-cosx)​

Answers

Answered by Anonymous
2

sinx = x -x^3/3! +x^5/5! -x^7/7! +…(sinx)/x = 1 - x^2/3! +x^4/5! -x^6/7! +…

Clearly lim, x—->0 of (sinx)/x = 1.

Then lim, x—->0 of ((sinx)/x)^((sinx)/x -sinx)) = 1^(1–0) = 1^1 = 1.

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