Question

what is the value of limit X tends to -2
X+2 divide by x^3 +8​

Answer 1

Answer:

GIVEN FUNCTION-

$lim_{x - > - 2 }( \frac{x + 2}{ {x}^{3} + 8} )$

LET'S FACTORIES -

$= lim_{x - > - 2}( \frac{x + 2}{(x + 2)( {x}^{2} - 2x + 4)} ) \\ \\ = lim_{x - > - 2}( \frac{1}{ {x}^{2} - 2x + 4 } ) \\ \\ = \frac{1}{ {( - 2)}^{2} - 2( - 2) + 4 } \\ \\ = \frac{1}{4 + 4 + 4} = \frac{1}{12}$

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